The Raptors have signed and subsequently waived free agent guard Saben Lee, the team announced today.
The 38th overall pick in the 2020 draft, Lee spent his first two NBA seasons with the Pistons, first on a two-way contract and then on a standard deal. He appeared in 85 total games for the team, averaging 5.6 points, 2.9 assists, and 2.4 rebounds in 16.3 minutes per contest, with a shooting line of .434/.265/.731.
Lee was traded from Detroit to Utah last month in the Bojan Bogdanovic deal and was subsequently released by the Jazz. After clearing waivers, he signed a training camp contract with the Suns on Tuesday, but his stint in Phoenix was short-lived — he was cut by the team on Thursday.
Despite the fact that he spent time on three rosters leading up to the 2022/23 season, Lee’s G League rights weren’t held by any team until he signed with the Raptors, his fourth club of the last month. Toronto signed Lee to an Exhibit 10 contract that will ensure he receives a bonus worth up to $50K if he spends at least 60 days with the Raptors 905.
The Raptors didn’t have to make a corresponding roster move to make room for Lee, since the 15-man limit still won’t apply until after Monday’s cut-down deadline. Since Lee won’t clear waivers until Tuesday, Toronto will be on the hook for one day’s worth of dead money for him — that portion of prorated salary figures to be worth $10,552.